Practicing Success
Which one of the following will yield the highest splitting of d orbitals? |
\(S^{2–}\) \(OH^–\) \(CN^–\) \(EDTA^{4–}\) |
\(CN^–\) |
The correct answer is option 3. \(CN^–\). In coordination chemistry, the splitting of d orbitals is a phenomenon known as crystal field splitting. It occurs when a central metal ion in a coordination complex is surrounded by ligands. The nature of the ligands determines the extent of splitting of the metal ion's d orbitals. Ligands can be classified into two categories based on their ability to cause d orbital splitting: 1. Strong-field ligands: These ligands cause a large energy difference (splitting) between the lower-energy set of d orbitals (\(t_{2g}\)) and the higher-energy set (\(e_g\)). Strong-field ligands typically have lone pair electrons or π-acceptor groups that interact strongly with the metal d orbitals. (1) \(S^{2-}\) (sulfide): Sulfide is generally a weak-field ligand. It does not cause significant splitting of d orbitals. (2) \(OH^-\) (hydroxide): Hydroxide is also a weak-field ligand, and it does not lead to large d orbital splitting. (3) \(CN^-\) (cyanide): Cyanide is a strong-field ligand. The carbon and nitrogen atoms in the cyanide ion form a strong π bond with the metal, leading to significant d orbital splitting. |