The random variable X has a probability distribution P(X) of the following form, where k is some number: $P(X=x)=\left\{\begin{array}{ccc}2 k, & \text { if } & x=0 \\ 3 k, & \text { if } & x=1 \\ 4 k, & \text { if } & x=2 \\ 0, & \text { if } & \text { otherwise }\end{array}\right.$ Then P(X ≤ 1) is equal to:

$\frac{2}{9}$ 1 $\frac{5}{9}$ 0

$\frac{5}{9}$

The correct answer is Option (3) → $\frac{5}{9}$