If $a^2+b^2+49 c^2+18=2(b-28 c-a)$ then the value of $(a+b-7 c)$ is: |
4 3 2 1 |
4 |
If $a^2 +b^2 +49c^2 + 18 = 2(b - 28c - a)$ then the value of (a - b - 7c) = ? we can find the values of the variables by = Coefficient of variables on right sides divide by coefficient of same variable on left side along with the signs as given below = b = 1 a = -1 c = -\(\frac{28}{49}\) = -\(\frac{4}{7}\) (a + b - 7c) = (-1 + 1 - 7(-\(\frac{4}{7}\))) = 4 |