The remainder when (672 + 541 + 383 + 295 + 101 + 86) is divided by 3…

The correct answer is Option (3) → 2

Compute each term modulo 3:

672 ≡ 0 (mod 3) since 6+7+2=15 divisible by 3

541: 5+4+1 = 10 → 10 mod 3 → 541 ≡ 1 (mod 3)

383: 3+8+3=14 → 14 mod 3 = 2 → 383 ≡ 2 (mod 3)

295: 2+9+5=16 → 16 mod 3 = 1 → 295 ≡ 1 (mod 3)

101: 1+0+1=2 → 2 mod 3 = 2 → 101 ≡ 2 (mod 3)

86: 8+6=14 → 14 mod 3 = 2 → 86 ≡ 2 (mod 3)

Sum modulo 3: 0 + 1 + 2 + 1 + 2 + 2 = 8

8 mod 3 = 2

Therefore, the remainder is 2