If (x+\(\frac{1}{2}\))3 + (3x+\(\frac{2}{3}\))3 + (x-\(\frac{1}{6}\))3 = \(\frac{1}{12}\)(9x+2)(2x+1)(6x-1)
find the value of x2.
Answer & explanation
Correct answer: option 2
If a3 + b3 + c3 = 3abc
then a + b + c = 0
x+\(\frac{1}{2}\)+3x+\(\frac{2}{3}\)+x-\(\frac{1}{6}\) = 0
5x+\(\frac{1}{2}\)+\(\frac{2}{3}\)-\(\frac{1}{6}\)=0
x=\(\frac{-1}{5}\)
x2=(\(\frac{-1}{5}\))2 = \(\frac{1}{25}\)