What is the value of x for which the points A (-1, 3), B (2, x) and C (5, -1) are collinear? |
0 1 -1 2 |
1 |
The correct answer is Option (2) → 1 For three points to be collinear, the slopes between any two pairs must be equal. Given points:
Step 1: Slope of AC $m_{AC} = \frac{-1 - 3}{5 - (-1)} = \frac{-4}{6} = -\frac{2}{3}$ Step 2: Slope of AB $m_{AB} = \frac{x - 3}{2 - (-1)} = \frac{x - 3}{3}$ Step 3: Set slopes equal $\frac{x - 3}{3} = -\frac{2}{3}$ $x−3=−2$ $x=1$ Correct answer: 1 |