Current though 1V cell and through 2 Ω resistor respectively is |
2A, 1A 1A, 2A 2A, 2A 1A, 1A |
1A, 1A |
In the given circuit potential at various points can be presented as Clearly, $I_1=\frac{-1-(-2)}{1}=1 \mathrm{~A}$ And $I_2=\frac{0-(-2)}{2}=1 \mathrm{~A}$ |