If x - \(\frac{1}{x}\) = 3\(\sqrt{5}\)
then find the value of x3 + \(\frac{1}{x^3}\)
Answer & explanation
Correct answer: option 2
⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\)
and
If x + \(\frac{1}{x}\) = a then ⇒ x3 + \(\frac{1}{x^3}\) = a3 - 3a
ATQ,
x - \(\frac{1}{x}\) = 3\(\sqrt{5}\), then
⇒ x + \(\frac{1}{x}\) = \(\sqrt {(3\sqrt{5})^2 + 4}\) = 7
⇒ ( x3 + \(\frac{1}{x^3}\) ) = 73 - 3 × 7 = 322