If corner points of a feasible region are (0, 0), (2, 0), $\left(\frac{20}{19}, \frac{45}{19}\right)$ and (0, 3), then
(A) Maximum value of $z=5 x+3 y$ is 10
(B) Minimum value of $z=5 x+3 y$ is 0
(C) Maximum value of $z=5 x+3 y$ is $\frac{235}{19}$ and minimum value is 0
(D) Maximum value of $z=5 x+3 y$ is 10 and minimum value is 0
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) - (B) and (C) Only
$Z=5x+3y$
| corner points | value of Z |
| $A(0,0)$ | $Z_A=0$ |
| $B(2,0)$ | $Z_B=10$ |
| $C(\frac{20}{19},\frac{45}{19})$ | $Z_C=\frac{235}{19}=12.368$ |
| $D(0,3)$ | $Z_D=9$ |
Z minimum = 0
Z maximum = $\frac{235}{19}$
⇒ B, C correct