Magnetic moment values for $[Fe(H_2O)_6]^{3+}$ and $[Fe(CN)_6]^{3-}$ are......
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 5.92 BM and 1.74 respectively
First determine the spin state of each complex.
1. $[Fe(H_2O)_6]^{3+}$
- Fe³⁺ → $d^5$
- $H_2O$ = weak field ligand
- High spin complex
- Number of unpaired electrons = 5
Magnetic moment:
$\mu = \sqrt{n(n+2)} = \sqrt{5(7)} \approx 5.92 \text{ BM}$
2. $[Fe(CN)_6]^{3-}$
- Fe³⁺ → $d^5$
- $CN^-$ = strong field ligand
- Low spin complex
- Number of unpaired electrons = 1
Magnetic moment:
$\mu = \sqrt{1(3)} \approx 1.74 \text{ BM}$
Final Answer: 5.92 BM and 1.74 respectively