In the given figure, AP and BP are tangents to a circle with centre O. If ∠APB = 62° then the measure of ∠AQB is:
Answer & explanation
Correct answer: option 4
In quadrilateral AOBP ,
∠PAO + ∠PBO + ∠AOB + ∠APB = 360º
90º + 90º + ∠AOB + 62º = 360º
∠AOB = 118º
We know that by same arc angle made at center is double to the angle made at circumference.
∠AQB = \(\frac{∠AOB}{2}\)
= \(\frac{ 118º}{2}\)
= 59º