The product (X) in the following reaction is

The correct answer is Option (2) → 

Complete statement:

The given reaction converts aniline into bromobenzene.

Reasoning:

Step 1: Diazotization

Aniline ($C_6H_5NH_2$) reacts with $NaNO_2$ and $HCl$ at low temperature to form benzene diazonium chloride ($C_6H_5N_2^+Cl^-$).

Step 2: Sandmeyer reaction

The diazonium salt reacts with $Cu_2Br_2 / HBr$, in which the diazonium group ($-N_2^+$) is replaced by $Br$, releasing nitrogen gas ($N_2$).

Reaction type: Sandmeyer substitution

So,

$C_6H_5NH_2→C_6H_5N_2^+Cl^-→ C_6H_5Br + N_2$

Therefore, the correct product X = bromobenzene ($C_6H_5Br$).