$\int\limits_0^2\left(x^2+1\right) d x$ is equal to
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{14}{3}$
$\int\limits_0^2\left(x^2+1\right) d x=\left[\frac{x^3}{3}+x\right]_0^2$
$⇒\frac{8}{3}+2-0=\frac{8+6}{3}=\frac{14}{3}$