Rate of a particular reaction is represented by

\(\text{Rate = }K[A]^0[B]^{2}\)

The unit of rate constant \(K\) in this case will be

\(mol^{-1}L\, \ sec^{-1}\)

The correct answer is option 1. \(mol^{-1}L\, \ sec^{-1}\).

Given,

Rate of the reaction is

\(\text{Rate = }K[A]^0[B]^{2}\).

Thus, the order of the reaction \(= 0 + 2 = 2\)

Hence the reaction is of second order.

We know unit of rate of reaction is given by \((conc)^{1 - n}time^{-1}\)

Thus for a second order reaction, the unit will be

\((conc)^{1 - 2}time^{-1}\)

or, \((mol\, \ L^{-1})^{1 - n}time^{-1}\)

or, \(mol^{-1}L\, \ time ^{-1}\)

If we consider the time in seconds, then the units will be

\(mol^{-1}L\, \ sec ^{-1}\)