Rate of a particular reaction is represented by
\(\text{Rate = }K[A]^0[B]^{2}\)
The unit of rate constant \(K\) in this case will be
Answer & explanation
Correct answer: option 1
The correct answer is option 1. \(mol^{-1}L\, \ sec^{-1}\).
Given,
Rate of the reaction is
\(\text{Rate = }K[A]^0[B]^{2}\).
Thus, the order of the reaction \(= 0 + 2 = 2\)
Hence the reaction is of second order.
We know unit of rate of reaction is given by \((conc)^{1 - n}time^{-1}\)
Thus for a second order reaction, the unit will be
\((conc)^{1 - 2}time^{-1}\)
or, \((mol\, \ L^{-1})^{1 - n}time^{-1}\)
or, \(mol^{-1}L\, \ time ^{-1}\)
If we consider the time in seconds, then the units will be
\(mol^{-1}L\, \ sec ^{-1}\)