Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Linear Programming

Question:

The solution set of the inequality $-3 ≤ \frac{4-3 x}{3} ≤ 7$ is:

Options:

$\left[-\frac{17}{3}, \frac{13}{3}\right]$

$\left(-\frac{17}{3}, \frac{13}{3}\right)$

$\left(-\infty,-\frac{13}{3}\right)$

$\left(-\infty, \frac{13}{3}\right)$

Correct Answer:

$\left[-\frac{17}{3}, \frac{13}{3}\right]$

Explanation:

The correct answer is Option (1) → $\left[-\frac{17}{3}, \frac{13}{3}\right]$