The solution set of the inequality $-3 ≤ \frac{4-3 x}{3} ≤ 7$ is:

$\left[-\frac{17}{3}, \frac{13}{3}\right]$

The correct answer is Option (1) → $\left[-\frac{17}{3}, \frac{13}{3}\right]$

$-3 \le \frac{4-3x}{3} \le 7$

$-9 \le 4 - 3x \le 21$

$-13 \le -3x \le 17$

$\frac{13}{3} \ge x \ge -\frac{17}{3}$

$-\frac{17}{3} \le x \le \frac{13}{3}$

$\text{Solution set} = \left[-\frac{17}{3}, \frac{13}{3}\right]$