The solution set of the inequality $-3 ≤ \frac{4-3 x}{3} ≤ 7$ is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\left[-\frac{17}{3}, \frac{13}{3}\right]$
$-3 \le \frac{4-3x}{3} \le 7$
$-9 \le 4 - 3x \le 21$
$-13 \le -3x \le 17$
$\frac{13}{3} \ge x \ge -\frac{17}{3}$
$-\frac{17}{3} \le x \le \frac{13}{3}$
$\text{Solution set} = \left[-\frac{17}{3}, \frac{13}{3}\right]$