Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Find the mean proportion of \(\frac{1}{4}\) and \(\frac{1}{81}\) .

Options:

\(\frac{1}{22}\)

\(\frac{1}{11}\)

\(\frac{1}{18}\)

\(\frac{1}{16}\)

Correct Answer:

\(\frac{1}{18}\)

Explanation:

Mean proportion of a and b = \(\sqrt {a × b }\)

⇒ Mean proportion = \(\sqrt {\frac{1}{4} × \frac{1}{81}}\)

                               = \(\frac{1}{2 × 9}\)  = \(\frac{1}{18}\)