Arrange the following steps involved in working of photodiode in sequential order of their occurrence.
A. Electron hole pair generation
B. Absorption of photons
C. Illumination with light
D. Separation of electron-hole pair
E. Collection of electrons in n-side and holes in p-side.
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → C, B, A, D, E
A photodiode is a reverse-biased p-n junction whose current is controlled by light. The steps follow cause and effect:
C. Illumination with light — light falls on the junction.
B. Absorption of photons — photons with energy greater than the band gap are absorbed.
A. Electron hole pair generation — each absorbed photon lifts an electron to the conduction band and leaves a hole behind.
D. Separation of electron-hole pair — the junction field pulls the electron and the hole apart before they recombine.
E. Collection of electrons in n-side and holes in p-side — the charges collected on the two sides give the photocurrent.
So the order is C, B, A, D, E.
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.
NCERT (Pre-rationalised edition, 2022-23):
Optoelectronic Junction Devices – “… When the photodiode is illuminated with light (photons) with energy (hν) greater than the energy gap (Eg) of the semiconductor, then electron-hole pairs are generated due to the absorption of photons. … Due to electric field of the junction, electrons and holes are separated before they recombine. The direction of the electric field is such that electrons reach n-side and holes reach p-side. Electrons are collected on n-side and holes are collected on p-side giving rise to an emf.”