A chord of a circle is equal to its radius of length 9 cm. Find the angle subtended by it in major segment.

30°

The length of chord = radius = 9 cm

= It forms an equilateral triangle with each angle at \({60}^\circ\)

= The angle subtended by the chord at the center = \({60}^\circ\)

By using theorem, the angle subtended in the major segment is half of the angle subtended at the center.

= \(\frac{60}{2}\) = \({30}^\circ\)

Therefore, the angle subtended by the chord in the major segment is \({30}^\circ\).