A thermally insulated container is divided into parts by a screen. In one part the pressure and temperature are P and T for an ideal gas filled. In the second part it is vacuum. If now a small hole is created in the screen, then the temperature of the gas will be :

remain same

In second part there is a vacuum, i.e. P = 0. So work done in expansion = P\(\Delta\) V = 0. Also, \(\Delta Q\) = 0. From the first las of thermodynamics, \(\Delta U\) = 0 i.e. temperature of an ideal gas remains same due to free expansion.