Let $f(x)=\frac{\sin x}{x}, x \neq 0$. Then, f(x) can be continuous at x = 0, if

f(0) = 0 f(0) = 1 f(0) = 2 f(0) = -2

f(0) = 1

f(x) will be continuous at x = 0, if $\lim\limits_{x \rightarrow 0} f(x)=f(0)$ $\Rightarrow \lim\limits_{x \rightarrow 0} \frac{\sin x}{x}=f(0) \Rightarrow f(0)=1$