If sinA =\(\frac{48}{73}\) . Then find the value of 11tanA .

\(\frac{4}{27}\)  \(\frac{48}{5}\)  \(\frac{4}{5}\)  \(\frac{48}{15}\)

\(\frac{48}{5}\)

sinA =\(\frac{48}{73}\) =\(\frac{P}{H}\)   [ Triplet 48 , 55 , 73 ] B = 55  ⇒ 11tanA = 11 × \(\frac{P}{B}\) = 11 × \(\frac{48}{55}\) = \(\frac{48}{5}\)