Find the mean proportion between (6 + √8) and (3-√2).

Mean proportion of A and B = \(\sqrt {A\;\times\;B }\)

Mean proportion = \(\sqrt {(6+\sqrt{8})\; \times\; (3-\sqrt{2}) }\)   =  \(\sqrt {2(3+\sqrt{2})\; \times\; (3-\sqrt{2}) }\) 

                       =  \(\sqrt {2(9\;-\;2) }\) = \(\sqrt {14 }\)