Find the mean proportion between $(6 + \sqrt{8})$ and $(3-\sqrt{2})$.

$2\sqrt{12}$ $\sqrt{14}$ $(6 + \sqrt{8})$ $\sqrt{15}-7$

$\sqrt{14}$

Mean proportion of A and B = \(\sqrt {A\;\times\;B }\) Mean proportion = \(\sqrt {(6+\sqrt{8})\; \times\; (3-\sqrt{2}) }\)   =  \(\sqrt {2(3+\sqrt{2})\; \times\; (3-\sqrt{2}) }\)                         =  \(\sqrt {2(9\;-\;2) }\) = \(\sqrt {14 }\)