Practicing Success
Consider a thin uniform spherical layer of mass M and radius R. The potential energy of gravitational interaction of matter forming this shell is |
$-\frac{GM^2}{R}$ $-\frac{1}{2} \frac{GM^2}{R}$ $-\frac{3}{5} \frac{GM^2}{R}$ $-\frac{2}{3} \frac{GM^2}{R}$ |
$-\frac{1}{2} \frac{GM^2}{R}$ |
Let us consider the shell when a mass m is already piled on it by the agency. If V is the potential on the shell, then $V=-\frac{Gm}{R}$ To add a mass dm further we have dW = Vdm $\Rightarrow dW=-\frac{Gm}{R} dm $ $\Rightarrow W=-\frac{G}{R} \int\limits_0^{M} mdm$ $\Rightarrow W=-\frac{1}{2} \frac{GM^2}{R}$ = Potential Energy of Interaction. |