Practicing Success
Practicing Success
CUET Preparation Today
The number of real solutions of the equation $\sin (e^x)=2^x+2^{-x}$, is _____. |
| 0 |
We know that AM ≥ GM $∴\frac{2^x+2^{-x}}{2}≥\sqrt{2^x×2^{-x}}$ $⇒2^x+2^{-x}≥2$ But, $\sin (e^x) ≤1$ Thus, $\sin (e^x) ≠2^x + 2^{-x}$ for any $x ∈ R$. Hence, the given equation has no solution. |
