Practicing Success
Practicing Success
CUET Preparation Today
If $x + \frac{1}{x} = 2K$, then what is the value of $x^4 +\frac{1}{x^4}$ ? |
$16K^4 -16K^2 - 1$ $8K^4+4K^2 - 1$ $16K^4 - 16K^2 +2$ $16K^4 -4K^2 - 1$ |
$16K^4 - 16K^2 +2$ |
If $x + \frac{1}{x} = 2K$ then what is the value of $x^4 +\frac{1}{x^4}$ = ? $(x + \frac{1}{x}) = x$ (x2 + x-2) = (x)2 - 2 = b = (x4 + x-4) = b2 - 2 If $x + \frac{1}{x} = 2K$ (x2 + x-2) = (2k)2 - 2 = 4k2 - 2 $x^4 +\frac{1}{x^4}$ = (4k2 - 2)2 - 2 $x^4 +\frac{1}{x^4}$ = 16k4 + 4 - 16k - 2 $x^4 +\frac{1}{x^4}$ = $16K^4 - 16K^2 +2$ |
