CUET Preparation Today
Find the domain of the function $f(x)=\frac{x^2+3x+5}{x^2-5x+4}$. |
$R – \{3, 4\}$ $R – \{1, 4\}$ $R – \{4\}$ None of these |
$R – \{1, 4\}$ |
The correct answer is Option (2) → $R – \{1, 4\}$ Since $x^2 –5x + 4 = (x – 4) (x –1)$, the function f is defined for all real numbers except at $x = 4$ and $x = 1$. Hence the domain of f is $R – \{1, 4\}$. |
