If $A=\begin{bmatrix}2+x & y\\1 & 5\end{bmatrix}$ and $B=\begin{bmatrix}3+y & x-1\\2 & 10 \end{bmatrix}$ such that B=2A, then value of x and y are respectively :

-1, -1

The correct answer is option (3) → -1, -1

$B=2A⇒\begin{bmatrix}3+y & x-1\\2 & 10 \end{bmatrix}=\begin{bmatrix}4+2x & 2y\\2 & 10\end{bmatrix}$

on comparison

$x-1=2y$

$⇒x=1+2y$

$3+y=4+2x$

$3+y=4+2+4y$

$-3=3y⇒y=-1$

$⇒x=-1$

$x=-1,y=-1$