Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

Third excited state(n=4) to second excited state (n=3) $\Rightarrow \frac{1}{\lambda_1} = R(\frac{1}{3^2} - \frac{1}{4^2}) = \frac{7R}{144}$

Second excited state(n=3) to first excited state (n=2)

$\Rightarrow \frac{1}{\lambda_2} = R(\frac{1}{2^2} - \frac{1}{3^2}) = \frac{5R}{36}$

$\Rightarrow \frac{\lambda_1}{\lambda_2} = \frac{5R/36}{7R/144} = \frac{20}{7}$