Shankar travelled from P to Q at an average speed of 50 km/h.  He travelled the first 60% of the distance in two-third of the time and the rest at a constant speed of x km/h.  The value of x is?

60 km/h

60% = \(\frac{3}{5}\)

Let total distance = 500 km

Time = \(\frac{500}{50}\) = 10 h

(PO = 60% distance, OQ = remaining distance)

Time (PO) = 10 × \(\frac{2}{3}\) = \(\frac{20}{3}\) h

Time (OQ) = 10 - \(\frac{20}{3}\) = \(\frac{10}{3}\) h

OQ Distance = 500 × \(\frac{2}{5}\) = 200 km

Speed(x) = \(\frac{200}{\frac{10}{3}}\) = 60 km/h