Shankar travelled from P to Q at an average speed of 50 km/h. He travelled the first 60% of the distance in two-third of the time and the rest at a constant speed of x km/h. The value of x is?
Answer & explanation
Correct answer: option 2
60% = \(\frac{3}{5}\)
Let total distance = 500 km
Time = \(\frac{500}{50}\) = 10 h
(PO = 60% distance, OQ = remaining distance)
Time (PO) = 10 × \(\frac{2}{3}\) = \(\frac{20}{3}\) h
Time (OQ) = 10 - \(\frac{20}{3}\) = \(\frac{10}{3}\) h
OQ Distance = 500 × \(\frac{2}{5}\) = 200 km
Speed(x) = \(\frac{200}{\frac{10}{3}}\) = 60 km/h