The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T1 and T2 (T1 > T2 ). The rate of heat transfer, dQ/dt through the rod in a steady state is given by:
Answer & explanation
Correct answer: option 3
In steady state \(\frac{dQ}{dt} = \frac{kA(T_1-T_2)}{L}\)