When the electronic configuration of a transition metal element X in +3 oxidation state is $[Ar]3d^5$, what is its atomic number?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 26
In transition metals, electrons are removed first from the $4s$ orbital and then from the $3d$ orbital during ion formation.
The given configuration is for $\mathbf{X^{3+}}$:
$X^{3+} = [Ar] \, 3d^{5}$
To find the atomic number, we determine the configuration of the neutral atom $X$.
During ion formation:
- First, electrons are removed from $4s$
- Then from $3d$
So while forming $X^{3+}$:
Removal of $3$ electrons occurs as:
- $2$ electrons from $4s$
- $1$ electron from $3d$
Hence, the neutral atom must have been:
$[Ar] \, 3d^{6} \, 4s^{2}$
This configuration belongs to Iron $(Fe)$
Atomic number of $Fe = 26$