A certain sum of money becomes 1.44 times of itself in 2 years. Find the rate of interest per annum.
Answer & explanation
Correct answer: option 2
ATQ,
P = 1 → 2yr → 1.44 (Amount)
↓ ↓
×1/2 square root*
↓ ↓
P = 1 → 1yr → 1.2times
Interest = 1.2 - 1 = 0.2
Interest rate = \(\frac{0.2}{1}\) × 100 = 20%
OR
Amount = P (1+ \(\frac{r}{100}\))t
ATQ,
⇒ 1.44P = P (1+ \(\frac{r}{100}\))2
⇒ 1.44 = (1+ \(\frac{r}{100}\))2
⇒ 1.2 = (1+ \(\frac{r}{100}\))1
⇒ Interest = 1.2 - 1 = 0.2
⇒ Interest rate = \(\frac{0.2}{1}\) × 100 = 20%