Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
c |
$ \text{ For central Maximum } sin\theta = \frac{\lambda}{d} $ $\text{ Angular width is }2\theta = \frac{2\lambda}{d}$ $\text{Linear width is} = 2D\theta = \frac{2\lambda D}{d}$ $\text{According to the question} \frac{2\lambda D}{d} = d $ $\Rightarrow D = \frac{d^2}{2\lambda}$ |
