Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

If a, b, c, d are four positive real numbers such that abcd = 1, then minimum value of (1+ a) (1 + b) (1 + c) (1 + d) is

Options:

8

12

16

20

Correct Answer:

16

Explanation:

Applying AM ≥ GM

$\frac{1+a}{2} \geq(a)^{1 / 2}, \frac{1+b}{2} \geq(b)^{1 / 2}, \frac{1+c}{2} \geq(c)^{1 / 2}, \frac{1+d}{2} \geq(d)^{1 / 2}$

Multiplying all focus (1 + a) (1 + b)(1 + c)(1 + d) ≥ 16