Practicing Success
Practicing Success
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Let A = {(x, y) | y = ex, x ∈ R} and B = {(x, y) : y= e-x, x ∈ R}. Then |
A ∩ B = $\phi$ A ∩ B ≠ $\phi$ A ∪ B = R2 none of these |
A ∩ B ≠ $\phi$ |
y = ex and y = e–x will intersect at one point A ∩ B ≠ $\phi$ Hence (2) is the correct answer. |
