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-- Mathematics - Section A
Application of Integrals
The area of region bounded by the curves $y=x^2+2$, y = -x, x = 0 and x = 1 is
$\frac{1}{16}$
$\frac{3}{16}$
$\frac{17}{6}$
$\frac{5}{16}$
The correct answer is Option (3) - $\frac{17}{6}$