Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Probability

Question:

Three cards are drawn simultaneously from a well shuffled pack of cards. Find the probability of all the three being Honor cards.

Options:

\(\frac{28}{575}\)

\(\frac{14}{575}\)

\(\frac{28}{1105}\)

\(\frac{14}{1105}\)

Correct Answer:

\(\frac{28}{1105}\)

Explanation:

Honours card – Ace, King, Queen and jack.

Spots card – Numbered card {2 to10}

Total honor cards = 16

Number of ways of drawing 3 honor cards = 16C3.

Reqd. probability = \(\frac{^{16} \mathrm{ C }_3}{^{52} \mathrm{ C }_3}\)

                         = \(\frac{28}{1105}\)

Hence, option C is correct.