Let R be the relation on the set R of all real numbers defined by a R b if and only if $|a-b|≤1$. Then R is ___________.
Answer & explanation
Correct answer: option 4
$|a-a|=a<1$
Therefore, $a\,R\,a\,∀\,a∈R$
Therefore, R is reflexive.
Again a R b, $|a-b|≤1⇒|b-a|≤1⇒b\,R\,a$
Therefore, R is symmetric.
Again $1\,R[\frac{1}{2}]$ and $[\frac{1}{2}]R\,1$ but $[\frac{1}{2}]≠1$
Therefore, R is not anti-symmetric.
Further, 1 R 2 and 2 R 3 but $[\frac{1}{R3}]$, [Because, |1 - 3| = 2 > 1]
Hence, R is not transitive.