CUET Preparation Today
The function xx decreases on the interval |
(0, e) (0, 1) $(0, \frac{1}{e})$ None of these |
$(0, \frac{1}{e})$ |
The correct answer is Option 3: $(0, \frac{1}{e})$ ⇒ $f'(x) = x^x[1+\log x]$ 1+ log$x$ <0 ⇒log$x$ < −1 ⇒x<1/e Hence, decreasing on (0, 1/e) |
