Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Algebra

Question:

For the system of equations AX = B, which of the following is correct?

Options:

If A is a singular matrix, then AX = B has a unique solution.

If A is a non-singular matrix, then AX = B has infinitely many solutions.

If A is a non-singular matrix, then AX = B has a unique solution.

If A is a singular matrix, then AX = B is always consistent.

Correct Answer:

If A is a non-singular matrix, then AX = B has a unique solution.

Explanation:

The correct answer is Option (3) → If A is a non-singular matrix, then AX = B has a unique solution.

$\text{For the system }AX=B:$

$\text{If }A\text{ is non–singular }(|A|\neq 0),\text{ then }X=A^{-1}B\text{ is uniquely determined.}$

$\text{If }A\text{ is singular }(|A|=0),\text{ the system may have no solution or infinitely many solutions, but not a unique one.}$

Correct statement:

If A is a non-singular matrix, then AX = B has a unique solution.