For the system of equations AX = B, which of the following is correct? |
If A is a singular matrix, then AX = B has a unique solution. If A is a non-singular matrix, then AX = B has infinitely many solutions. If A is a non-singular matrix, then AX = B has a unique solution. If A is a singular matrix, then AX = B is always consistent. |
If A is a non-singular matrix, then AX = B has a unique solution. |
The correct answer is Option (3) → If A is a non-singular matrix, then AX = B has a unique solution. $\text{For the system }AX=B:$ $\text{If }A\text{ is non–singular }(|A|\neq 0),\text{ then }X=A^{-1}B\text{ is uniquely determined.}$ $\text{If }A\text{ is singular }(|A|=0),\text{ the system may have no solution or infinitely many solutions, but not a unique one.}$ Correct statement: If A is a non-singular matrix, then AX = B has a unique solution. |