If $x-\frac{2}{x}=4,$ then what will be the value of $x^2+\frac{4}{x^2}$ ?
Answer & explanation
Correct answer: option 1
If $x-\frac{2}{x}=4,$
then what will be the value of $x^2+\frac{4}{x^2}$ = ?
we know that,
If, $(x - \frac{1}{x}) = a$
then, (x2 + x-2) = (a)2 + 2
So, If $x-\frac{2}{x}=4,$
then, $x^2+\frac{4}{x^2}$ = (4)2 + 2 × 2 = 16 + 4 = 20