Practicing Success
If $x-\frac{2}{x}=4,$ then what will be the value of $x^2+\frac{4}{x^2}$ ? |
20 18 12 8 |
20 |
If $x-\frac{2}{x}=4,$ then what will be the value of $x^2+\frac{4}{x^2}$ = ? we know that, If, $(x - \frac{1}{x}) = a$ then, (x2 + x-2) = (a)2 + 2 So, If $x-\frac{2}{x}=4,$ then, $x^2+\frac{4}{x^2}$ = (4)2 + 2 × 2 = 16 + 4 = 20 |