CUET Preparation Today
When 3 coins are tossed simultaneously, the probability of having 3 heads is: |
0 1 $\frac{7}{8}$ $\frac{1}{8}$ |
$\frac{1}{8}$ |
$\text{Number of coins}=3.$ $\text{Total outcomes}=2^3=8.$ $\text{Sample space}=\{HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\}.$ $\text{Favourable outcome for 3 heads}=1\;(HHH).$ $P(\text{3 heads})=\frac{1}{8}.$ $P(\text{3 heads})=\frac{1}{8}.$ |
