In the given figure, if AC, DE are parallel and ∠CAB = 38° , then the value of ∠ABC + 5∠CBD is:
Answer & explanation
Correct answer: option 3
We have,
∠CAB = 38
∠ABC = b
∠CBD = a
∠CAB = 2a
According to the question,
2a = 38o
∠CBD = a = 19o
∠CAB + ∠ABD = 180 (Because AC and BD are parallel)
⇒ 2a + b + a = 180o
⇒ 38 + b + 19 = 180o
⇒ b = 180 - 57
⇒ b = 123o
∴∠ABC = 123o
Now, ∠ABC + 5 ∠CBD
= 123 + 5 × 19
= 123 + 95 = 218o