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Integrating factor of the differential equation $\cos x \frac{d y}{d x}+y \sin x=1$, is |
$\sin x$ $\sec x$ $\tan x$ $\cos x$ |
$\sec x$ |
We have, $\frac{d y}{d x}+(\tan x) y=\sec x$ ∴ Integrating factor = $e^{\int \tan x d x}=e^{\log \sec x}=\sec x$ |
