Target Exam

CUET

Subject

General Aptitude Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 2D/3D

Question:

Match List-I with List-II

List-I (Shapes)

List-II (Area/Perimeter/Diagonal/slant height)

(A) Trapezium

(I) $\sqrt{l^2 + b^2 + h^2}$

(B) Sector of a circle

(II) $\sqrt{h^2 + (R − r)^2}$

(C) Cuboid

(III) $\frac{1}{2}h(a + b)$

(D) Frustum of cone

(IV) $(\frac{θ}{360°})×2πr$

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(IV), (C)-(III), (D)-(II)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Correct Answer:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Explanation:

The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

List-I (Shapes)

List-II (Area/Perimeter/Diagonal/slant height)

(A) Trapezium

(III) $\frac{1}{2}h(a + b)$

(B) Sector of a circle

(IV) $(\frac{θ}{360°})×2πr$

(C) Cuboid

(I) $\sqrt{l^2 + b^2 + h^2}$

(D) Frustum of cone

(II) $\sqrt{h^2 + (R − r)^2}$

(A) Trapezium: The area of a trapezium is calculated as half the product of the height and the sum of its parallel sides ($a$ and $b$).

  • Formula: $\frac{1}{2}h(a+b)$
  • Match: (A) – (III)

(B) Sector of a circle: The length of the arc of a sector with radius $r$ and angle $\theta$ is a fraction of the total circumference ($2\pi r$).

  • Formula: $(\frac{\theta}{360^\circ}) \times 2\pi r$
  • Match: (B) – (IV)

(C) Cuboid: The diagonal of a cuboid represents the longest distance between two opposite corners, calculated using the dimensions of length ($l$), breadth ($b$), and height ($h$).

  • Formula: $\sqrt{l^2 + b^2 + h^2}$
  • Match: (C) – (I)

(D) Frustum of cone: The slant height ($l$) of a frustum (a cone with the top cut off) is determined by its vertical height ($h$) and the difference between the radii of the top ($r$) and bottom ($R$) circles.

  • Formula: $\sqrt{h^2 + (R-r)^2}$
  • Match: (D) – (II)