Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: Coordination Compounds

Question:

Match List I with List II

List I List II
A. \([Co(H_2NCH_2CH_2NH_2)_3]_2(SO_4)_3\) I. Tetracabonylnickel(0)
B. \([Ni(CO)_4]\) II. Mercury tetrathiocyanatocobaltate (III)
C. \([CoCl_2(en)_2]^+\) III. tris(ethane-1,2-diamine)cobalt(III) sulphate
D. \(Hg[Co(SCN)_4]\) IV. Dichloridobis(ethane-1,2-diamine)cobalt (III)

Choose the correct answer from the options given below:

Options:

A-I, B-III, C-IV, D-II

A-III, B-I, C-II, D-IV

A-III, B-I, C-IV, D-II

A-I, B-III, C-II, D-IV

Correct Answer:

A-III, B-I, C-IV, D-II

Explanation:

The correct answer is option 3. A-III, B-I, C-IV, D-II.

Let us break down each complex and its corresponding description:

A. \([Co(H_2NCH_2CH_2NH_2)_3]_2(SO_4)_3\):

This complex is a coordination compound containing cobalt (Co) as the central metal ion. The ligand in this complex is \(H_2NCH_2CH_2NH_2\), which is ethane-1,2-diamine or simply ethylenediamine (en). The complex has three en ligands coordinated to the cobalt ion, resulting in the formula \([Co(en)_3]^{3+}\). The complex is further stabilized by sulfate (\(SO_4^{2-}\)) ions. So, the name will be III. tris(ethane-1,2-diamine)cobalt(III) sulphate.

B. \([Ni(CO)_4]\):

This complex is a neutral coordination compound containing nickel (Ni) as the central metal ion. It consists of four carbon monoxide (CO) ligands coordinated to the nickel ion. Since there are no charges indicated, the complex is neutral. So, the name will be I. tetracarbonylnickel(0).

C. \([CoCl_2(en)_2]^+\):

This complex is a cationic coordination compound containing cobalt (Co) as the central metal ion. It has two chlorido (Cl-) ligands and two ethane-1,2-diamine (en) ligands coordinated to the cobalt ion. The overall charge of the complex is 1+ due to the presence of one excess positive charge. So, the name will be IV. dichloridobis(ethane-1,2-diamine)cobalt (III).

D. \(Hg[Co(SCN)_4]\):

This complex is a coordination compound containing cobalt (Co) as the central metal ion. It is coordinated to four thiocyanate (\(SCN^-\)) ligands. The complex has mercury (Hg) as the counter ion. So, the name will be II. mercury tetrathiocyanatocobaltate (III).

In summary:

A matches with III: \([Co(H_2NCH_2CH_2NH_2)_3]_2(SO_4)_3\) is "tris(ethane-1,2-diamine)cobalt(III) sulphate."

B matches with I: \([Ni(CO)_4]\) is "tetracarbonylnickel(0)."

C matches with IV: \([CoCl_2(en)_2]^+\) is "dichloridobis(ethane-1,2-diamine)cobalt (III)."

D matches with II: \(Hg[Co(SCN)_4]\) is "mercury tetrathiocyanatocobaltate (III)."

So, the correct match is 3. A-III, B-I, C-IV, D-II.