Practicing Success
Match List I with List II
Choose the correct answer from the options given below: |
A-i, B-iii, C-ii, D-iv A-iv, B-i, C-ii, D-iii A-iii, B-ii, C-iv, D-i A-i, B-iv, C-ii, D-iii |
A-iv, B-i, C-ii, D-iii |
The correct answer is option 2. A-iv, B-i, C-ii, D-iii. Let us delve into the details of each reaction and the associated metals: A. Wurtz Reaction: iv. \(Na\) The Wurtz reaction involves the coupling of two alkyl halides in the presence of sodium metal to form a new carbon-carbon bond. The general reaction is as follows: \(2R-X + 2Na \longrightarrow R-R + 2NaX \) Where \( R \) represents an alkyl group and \( X \) is a halogen. Sodium (Na) acts as the reducing agent in this reaction, promoting the formation of the carbon-carbon bond. This reaction is particularly useful for synthesizing symmetrical alkanes. The Sabatier-Senderens reaction refers to the hydrogenation of alkenes or alkynes to alkanes using a nickel catalyst. The reaction is typically carried out under conditions of elevated temperature and pressure. The general reaction is: \( R-CH=CH-R' + H_2 \overset{Ni}{\longrightarrow} R-CH_2-CH_2-R'\) Nickel (Ni) serves as the catalyst that facilitates the addition of hydrogen (H\(_2\)) to the carbon-carbon double or triple bonds, converting them into single bonds and thus forming alkanes. C. Frankland Reaction: ii. \(Zn\) The Frankland reaction involves the formation of organozinc compounds by the reaction of zinc with alkyl halides. The general reaction is: \(2R-X + 2Zn \longrightarrow R_2Zn + ZnX_2 \) Where \( R \) is an alkyl group and \( X \) is a halogen. Zinc (Zn) is crucial for the formation of the organozinc compound, which can be used in various organic synthesis reactions. D. Decarboxylation: iii. \(CaO + NaOH\) Decarboxylation is the process of removing a carboxyl group from a carboxylic acid, releasing carbon dioxide (CO\(_2\)). The reaction is often carried out using soda lime, a mixture of calcium oxide (CaO) and sodium hydroxide (NaOH). The general reaction is: \(R-COOH \overset{CaO + NaOH}{\longrightarrow} R-H + CO_2\) Soda lime facilitates the decarboxylation, making it a practical method for converting carboxylic acids into hydrocarbons. Thus, the correct matching is: 2. A-iv, B-i, C-ii, D-iii. |