Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

If A = \(\begin{bmatrix}6 & -2\\2 & 1 \end{bmatrix}\), then what is the value of |\(-4 { A }^{ T } \)|?

Options:

-160

160

-40

40

Correct Answer:

160

Explanation:

If Matrix A has size a × a and k is a constant, then |kA| = \( { k }^{ a } \) |A|

Then, |\(-4 { A }^{ T } \)| = \((-4)^{ 2 } \) |\( { A }^{ T } \)|

= \((-4)^{ 2 } \) |A | 

Because |\( { A }^{ T } \) = |A | 

|\(-4 { A }^{ T } \)| = 16 |A |

But |A| = 10

|\(-4 { A }^{ T } \)| = 160