The area enclosed by the curves $xy = 4, y=x, x=e^2$ and the x-axis, is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $10-2log_e4$
$xy = 4, y=x, x=e^2$
$x=y$ and $xy=4$
intersect at $x=4$
required area = $\frac{1}{2}×2×2+\int\limits_2^{e^2}\frac{4}{x}dx$
$=2+4[\log x]_2^{e^2}$
$=2+4(2-\log 2)$
$=10-2\log 4$