Let R be the set of real numbers. $f:R→R$ is given by $f(x)=(3-x^3)^{1/3}$, then $f^2$=composition of f with itself=
Answer & explanation
Correct answer: option 3
$f(f(x))=f((3-x^3)^{1/3})=((3-(3-x^3)^{1/3})^3)^{1/3}=(x^3)^{1/3}=x$
Let R be the set of real numbers. $f:R→R$ is given by $f(x)=(3-x^3)^{1/3}$, then $f^2$=composition of f with itself=
Correct answer: option 3
$f(f(x))=f((3-x^3)^{1/3})=((3-(3-x^3)^{1/3})^3)^{1/3}=(x^3)^{1/3}=x$